20x^2+17=97

Solution for 20x^2+17=97 equation:

20x^2+17=97

We move all terms to the left:

20x^2+17-(97)=0

We add all the numbers together, and all the variables

20x^2-80=0

a = 20; b = 0; c = -80;
Δ = b2-4ac
Δ = 02-4·20·(-80)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80}{2*20}=\frac{-80}{40}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80}{2*20}=\frac{80}{40}
=2
$